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51n-3n^2=156
We move all terms to the left:
51n-3n^2-(156)=0
a = -3; b = 51; c = -156;
Δ = b2-4ac
Δ = 512-4·(-3)·(-156)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(51)-27}{2*-3}=\frac{-78}{-6} =+13 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(51)+27}{2*-3}=\frac{-24}{-6} =+4 $
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